Question

Hydrogen bonds are formed in many compound e.g $H_{2}O$, $HF$ ,$N{H}_{3}O$. The bonding point of such compounds depends to large extent on the strength of hydrogen bond of the number of hydrogen bonds. The correct decreasing order of the boiling point of above compound is:

• A. $HF>H_{2}O>N{H}_3$
• B. $H_{2}O>HF>N{H}_3$
• C. $N{H}_3>HF>H_{2}O$
• D. $N{H}_3>H_{2}O>HF$

Answer 1

The correct option is B $H_{2}O>HF>N{H}_3$

Hydrogen bonding in $HF,H_{2}O,N{H}_3$ is in the order.

$H_{2}O>HF>N{H}_3$

And greater the hydrogen bonding,greater the hydrogen bonding,greater would be the bonding points,so therefore the order is $H_{2}O>HF>N{H}_3$points to be noted.

$H_{2}O$ forms ring due to $H-$ bonding

$HF$ has zig-zag structure.

$N{H}_3$ one low pair for $3-H$bond.