Hydrogen can be prepared with the metal zinc by using :

(i) acid (ii) alkali (iii) water

Give an equation in each case.

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Solution

Hydrogen can be prepared with metal zinc by using acid and the reaction is:

$Z n (s) + 2 H C l (a q) ⟶ Z n C l_{2} (a q) + H_{2} (g)$

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Similar questions

(a) Give one example, with an equation, of the displacement of hydrogen by a metal from an acid.
(b) Name two metals (other than zinc and iron) which can displace hydrogen from dilute hydrochloric acid?

From the metals copper, iron, magnesium, sodium and zinc, select a different metal in each case which:
(i) does not react with dilute hydrochloric acid.
(ii) can form 2+ and 3+ ions.
(iii) has a hydroxide that reacts with both acids and alkalis.
(iv) does not react with cold water but reacts with steam when heated.
Arrange the metals in increasing order of reactivity.

Hydrogen can be prepared with the help of cold water. Give a reaction of hydrogen with :

(a) a monovalent metal

(b) a divalent metal.

Give reason for the following

1. Nitric acid in the dilute form is not used in the laboratory preparation of hydrogen from metals.

2. Granulated zinc is preferred to metallic zinc in the preparation of hydrogen using dilute acid.

3. Hydrogen and alkali metals of group [1A] react with copper [II] oxide to give copper.

4. Hydrogen is collected by the downward displacement of water and not even though it is lighter than air.

5. A Mixture of hydrogen and chlorine can be separated by passage through a porous pot

Q. Hydrogen can be Prepared from dilute sulphuric acid using zinc but not lead. Give reason

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Preparation Using Zinc

Standard IX Chemistry

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Hydrogen can be prepared with the metal zinc by using : (i) acid (ii) alkali (iii) water Give an equation in each case.

Hydrogen can be prepared with metal zinc by using acid and the reaction is: Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)

Hydrogen can be prepared with the metal zinc by using :

(i) acid (ii) alkali (iii) water

Give an equation in each case.

Hydrogen can be prepared with metal zinc by using acid and the reaction is:

$Z n (s) + 2 H C l (a q) ⟶ Z n C l_{2} (a q) + H_{2} (g)$