Hydrogen chloride is liberated by the action of $H_{2} S O_{4}$ on metal and ammonium chlorides.

True

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False

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Solution

The correct option is A True
Sulphuric acid with metal chloride:
$H_{2} S O_{4} (c o n c .) + N a C l \to N a H S O_{4} + H C l (g)$
Sulphuric acid with ammonium chloride:
$H_{2} S O_{4} (c o n c .) + 2 N H_{4} C l \to (N H_{4})_{2} S O_{4} + 2 H C l (g)$
Therefore its true.

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