Hydrogen gas diffuses six times faster than gas A. The molar mass of gas A is ______ g/mol.

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Solution

The correct option is A
72
Graham's Law of Diffusion
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} F o r g a s A (r_{1}) = r F o r H_{2} (r_{2}) = 6 r \frac{r}{6 r} = \sqrt{\frac{2}{M_{1}}}, M_{1} = 36 \times 2 M_{1} = 72 g / m o l$

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