Hydrogen gas is filled in a balloon at 20- C- If temperature is made 40- C- pressure remaining same- what fraction of hydrogen will come outA- 0-25B- 0-5C- 0-75D- 0-07

The correct option is D 0.07As V ∞ T ∴V_2/V_1=T_2/T_1⇒ V_2 = ( 313/293 )V_1 Fraction of gas comes out = V_2 V_1/V_1= ( 313/293 )V_1 V_1/V_1=20/293=0.07. ...

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Byju's Answer

Standard XII

Physics

Pressure vs Velocity

Hydrogen gas ...

Question

Hydrogen gas is filled in a balloon at $20^{\circ} C$ . If temperature is made $40^{\circ} C$ , pressure remaining same, what fraction of hydrogen will come out

0.07

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0.25

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0.5

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0.75

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Solution

The correct option is A 0.07
As $V \infty T ∴ \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow V_{2} = (\frac{313}{293}) V_{1}$
Fraction of gas comes out $= \frac{V_{2} - V_{1}}{V_{1}} = \frac{(\frac{313}{293}) V_{1} - V_{1}}{V_{1}} = \frac{20}{293} = 0.07.$

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Hydrogen gas is filled in a balloon at 20∘C. If temperature is made 40∘C, pressure remaining same, what fraction of hydrogen will come out

The correct option is A 0.07As V∞T∴V2V1=T2T1⇒V2=(313293)V1 Fraction of gas comes out =V2−V1V1=(313293)V1−V1V1=20293=0.07.

Hydrogen gas is filled in a balloon at $20^{\circ} C$ . If temperature is made $40^{\circ} C$ , pressure remaining same, what fraction of hydrogen will come out

The correct option is A 0.07
As $V \infty T ∴ \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow V_{2} = (\frac{313}{293}) V_{1}$
Fraction of gas comes out $= \frac{V_{2} - V_{1}}{V_{1}} = \frac{(\frac{313}{293}) V_{1} - V_{1}}{V_{1}} = \frac{20}{293} = 0.07.$