Hydrogen peroxide in its reaction with KIO4 (I reaction) and NH2OH (II reaction) separately, it acts as a:
A
reducing agent in I, oxidising agent in II
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B
reducing agent in I, reducing agent in II
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C
oxidising agent in I, oxidising agent in II
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D
oxidising agent in I, reducing agent in II
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Solution
The correct option is A reducing agent in I, oxidising agent in II K+7IO4+H2O2→K+5IO3+H2O+O2 Here, H2O2 is reducing agent; KIO4 is reduced to KIO3. 1NH2OH+3H2O2→H+5NO3+4H2O In this reaction, H2O2 is oxidising agent, NH2OH is oxidised to HNO3.