Hydrogen peroxide is prepared in the laboratory by:

adding

M n O_{2}

to dilute

H_{2} S O_{4}

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passing

C O_{2}

into

B a O_{2}

paste in cold water

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adding

P b O_{2}

to an acidified

K M n O_{4}

solution

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adding

N a_{2} O_{2}

to cold water

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Solution

The correct option is C passing $C O_{2}$ into $B a O_{2}$ paste in cold water
Hydrogen peroxide can be prepared in the laboratory by the action of ice cold, dilute sulphuric acid on sodium peroxide or hydrated barium peroxide $(B a O_{2} . 8 H_{2} O)$ .
A calculated quantity of sodium peroxide is added in small quantities to $20 %$ ice cold solution of sulphuric acid. The reaction is as follows:
$N a_{2} O_{2} (s) + H_{2} S O_{4} \to N a_{2} S O_{4} (s) + H_{2} O_{2} (l)$
Most of the sodium sulphate separates out on cooling as crystals of $N a_{2} S O_{4} .10 H_{2} O$ .
Thus, $30 %$ of hydrogen peroxide containing small amount of sodium sulphate is obtained.
Barium peroxide is made into a thin paste and added slowly to ice-cold dilute sulphuric acid. The reaction is as follows:
$B a O_{2} (s) + H_{2} S O_{4} (a q) \to B a S O_{4} (s) + H_{2} O_{2} (l)$
Barium sulphate is allowed to settle down as a precipitate and filtered off. The filtrate obtained is a dilute solution of hydrogen peroxide. Phosphoric acid can be used in place of sulphuric acid. Alternatively, carbon dioxide gas may be passed through hydrated barium peroxide paste in ice cold water, in a slow stream.
$2 B a O_{2} (s) + 2 H_{3} P O_{4} (a q) \to B a (P O_{4})_{2} (s) + 3 H_{2} O_{2} (l)$
$B a O_{2} (s) + C O_{2} + H_{2} O_{2} \to B a C O_{3} (s) + H_{2} O_{2} (l)$
The precipitated barium peroxide or barium carbonate is filtered off which leaves hydrogen peroxide.

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