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Question

Hydrogen peroxide oxidises [Fe(CN)6]4- to [Fe(CN)6]3- in acidic medium but reduces [Fe(CN)6]3- to [Fe(CN)6]4- in alkaline medium. The other products formed are, respectively.


A

(H2O+O2) and (H2O+OH)

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B

H2O and (H2O+O2)

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C

H2O and (H2O+ OH)

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D

(H2O+O2) and H2O

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Solution

The correct option is B

H2O and (H2O+O2)


Explanation for the correct option:

Oxidation of Hydrocarbon: All hydrocarbons react in the air to form carbon monoxide and then through a series of reactions to form carbon dioxide.

  • The first step is always the reaction between a hydrocarbon and a hydroxyl radical.
  • With alkanes, the hydroxyl radical abstracts a hydrogen atom and forms a carbon-centered radical.
  • When Hydrogen peroxide oxidizes to [Fe+3(CN)6]3- in an acidic medium, the reaction takes place as:[Fe+2(CN)6]4-+H2O2+2H+[Fe+3(CN)6]3-+2H2O
  • From the above reaction, we see that hydrogen peroxide oxidizes to [Fe+3(CN)6]3- in an acidic medium the other product form is when Hydrogen peroxide reduces [Fe(CN)6]3-to[Fe(CN)6]4- in an alkaline medium, the reaction is:[Fe+3(CN)6]3-+H2O2+2OH-[Fe+2(CN)6]4-+O2+2H2O
  • From the above reaction, we see that Hydrogen peroxide oxidises [Fe(CN)6]3-to[Fe(CN)6]4- in an alkaline medium, and the other product form is H2O and O2.

(b) H2O and (H2O+O2): We can see from the given equation in acidic and in the alkaline medium the other product formed is H2O and (H2O+O2).

Explanation for the incorrect option:

(a) (H2O+O2) and (H2O+OH): From the given reaction we can see in acidic and in alkaline medium only H2O and (H2O+O2) is formed but there are no traces of OH- formed.

(c) H2O and (H2O+ OH): From the given reaction we can see in acidic and in alkaline medium only H2O and (H2O+O2) is formed but there are no traces of OH- formed.

(d) (H2O+O2) and H2O: From the given reaction (H2O+O2) and H2O are formed but not in this order. First H2O will form then H2O+O2 will form.

Hence, option (B) is the correct answer.


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