You visited us 2 times! Enjoying our articles? Unlock Full Access!

Chemical Reactivity

Hydrogen pero...

Question

Hydrogen peroxide solution having volume of $20$ mL reacts quantitatively with a solution of $K M n O_{4}$ of volume $20$ mL acidified with dilute $H_{2} S O_{4}$ . The same volume of the $K M n O_{4}$ solution is just decolourised by $10$ mL of $M n S O_{4}$ in a neutral medium simultaneously forming a dark-brown precipitate of hydrated $M n O_{2}$ . The brown precipitate is dissolved in $10$ mL of $0.2 M$ sodium oxalate under boiling condition in the presence of dilute $H_{2} S O_{4}$ . If the molarity of $H_{2} O_{2}$ is $x$ , then find the value of $10 x$ .

Open in App

Solution

The reactions involved are given below:
$2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O$
$2 K M n O_{4} + 3 M n S O_{4} + 2 H_{2} O \to 5 M n O_{2} + 2 H_{2} S O_{4} + K_{2} S O_{4}$
$M n O_{2} + N a_{2} C_{2} O_{4} + 2 H_{2} S O_{4} \to M n S O_{4} + N a_{2} S O_{4} + 2 H_{2} O + 2 C O_{2}$

Millimoles of $N a_{2} C_{2} O_{4} = 10 \times 0.2 = 2$
Milliequivalents of $N a_{2} C_{2} O_{4} = 4$
Milliequivalents of $M n O_{2} = 4$
Milliequivalents of $K M n O_{4} = 4$
Milliequivalents of $H_{2} O_{2} = 4$
Millimoles of $H_{2} O_{2} = 2$
Millimoles of $H_{2} O_{2} =$ Molarity $\times V_{m L}$
or $2 = Molarity \times 20$
or $Molarity = 0.1 M$
Hence, the value of $10 x$ is $10 \times 0.1 = 1$ .

Suggest Corrections

Similar questions

Q. A

20 mL

solution of hydrogen peroxide reacts quantitatively with a

20 mL

solution of

K M n O_{4}

acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is decolourised by

10 mL

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitated of hydrated

M n O_{2}

. The brown precipitate is dissolved in

20 mL

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

. Calculate the volume strength of

H_{2} O_{2}

Hydrogen peroxide solution (

20

mL) reacts quantitatively with a solution of

K M n O_{4}

(

20

mL) acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is just decolourised by

10

mL of

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

. The brown precipitate is dissolved in

10

mL of

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

Choose the correct balanced equation involved in the reaction.

Q. Hydrogen peroxide solution (20 mL) reacts quantitatively with a solution of

K M n O_{4}

(20 mL) acidified with dilute

H_{2} S O_{4}

, The same volume of the

K M n O_{4}

solution is just decolorized by 10mL of

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

The brown pecipitate is dissolved in 10 mL of 0.2 M sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

, Write the balanced equations involved in the reactions and calculate the molarity of

H_{2} O_{2}

Q. Hydrogen peroxide solution

(20 m L)

reacts quantitatively with a solution of

K M n O_{4} (20 m L)

acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is just decolourised by

10 m L

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

. The brown precipitate is dissolved in

10 m L

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

. Write the balanced equations involved in the reactions and calculate the molarity of

H_{2} O_{2}

Q. 10 mL of a solution of

H_{2} O_{2}

labelled '10 volume' just decolourises 100 mL of potassium permanganate solution acidified with dilute

H_{2} S O_{4}

. Calculate the amount of potassium permanganate in the given solution.

Join BYJU'S Learning Program