Hydrogenation of $C_{6} H_{5} C H O H C O O H$ over $R h - A l_{2} O_{3}$ gives :

C_{6} H_{5} C H_{2} C O O H

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C_{6} H_{11} C H O H C O O H

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C_{6} H_{5} C H O H C H_{2} O H

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C_{6} H_{11} C H_{2} C O O H

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Solution

The correct option is B $C_{6} H_{11} C H O H C O O H$
Hydrogenation of $C_{6} H_{5} C H O H C O O H$ over $R h - A l_{2} O_{3}$ gives $C_{6} H_{11} C H O H C O O H$
Hare $R h - A l_{2} O_{3}$ is used as a catalyst to hydrogenate phenyl group. This catalyst hydrogenates each carbon atom in phenyl group thus removing each double bond in phenyl group.

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