Question

Hydrogenation of vegetable ghee at ${25}^{o}C$ reduces the pressure of $H_2$ from 2 atm to 1.2 atm in 50 minutes.

The rate of reaction in terms of change of molarity per second is:

• A. $1.6\times {10}^{-2}atmmi{n}^{-1}$
• B. $3.3\times {10}^{-2}atmmi{n}^{-1}$
• C. $2.6\times {10}^{-3}atmmi{n}^{-1}$
• D. None of these

Answer 1

The correct option is A $1.6\times {10}^{-2}atmmi{n}^{-1}$

Rate of reaction $=\frac{\text{Change in pressure}}{\text{Time in minute}}=\frac{0.8}{50}$

$=1.6\times {10}^{-2}atmmi{n}^{-1}$

$(\because \Delta P=2-1.2=0.8)$

Hence, the correct option is $A$