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Orthoboric Acid

Hydrolysis of...

Question

Hydrolysis of $B C l_{3}$ gives $X$ which on treatment with sodium carbonate produces $Y$ . $X$ and $Y$ , respectively are:

H_{3} B O_{3}

and

N a B O_{2}

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H_{3} B O_{3}

and

N a_{2} B_{4} O_{7}

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B_{2} O_{3}

and

N a B O_{2}

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B_{2} O_{3}

and

N a_{2} B_{4} O_{7}

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Solution

The correct option is B $H_{3} B O_{3}$ and $N a_{2} B_{4} O_{7}$
$B C l_{3} + 3 H_{2} O \to H_{3} B O_{3} + 3 H C l$

$4 H_{3} B O_{3} + N a_{2} C O_{3} \to N a_{2} B_{4} O_{7} + 6 H_{2} O + C O_{2}$

Hence option $B$ is correct.

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