Question

Hydrolysis of one mole of peroxodisulfuric Acid (${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8$) produces

Answer 1

Hydrolysis of Peroxodisulfuric acid (${\mathbf{H}}_{\mathbf{2}}{\mathbf{S}}_{\mathbf{2}}{\mathbf{O}}_{\mathbf{8}}$)

1. Hydrolysis of one mole of Peroxodisulfuric acid (${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8$) produces one mole of Sulphuric acid (${\mathrm{H}}_2{\mathrm{SO}}_4$) and one mole of Peroxomonosulphuric acid (${\mathrm{H}}_2{\mathrm{SO}}_5$).
2. Chemical reaction involved:

$\underset{\mathrm{Peroxodisulphuric}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8\left(\mathrm{aq}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\to \underset{\mathrm{Sulphuric}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}+\underset{\mathrm{Peroxomonosulphuric}\mathrm{acid}}{{\mathrm{H}}_2{\mathrm{SO}}_5\left(\mathrm{aq}\right)}$

Therefore, one mole of Peroxodisulfuric acid produces Sulphuric acid (${\mathrm{H}}_2{\mathrm{SO}}_4$) and Peroxomonosulphuric acid (${\mathrm{H}}_2{\mathrm{SO}}_5$).