Hydrolysis of ozonide of 1-butene gives:

ethylene only

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acetaldehyde and formaldehyde

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propionaldehyde and formaldehyde

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acetaldehyde only

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Solution

The correct option is C propionaldehyde and formaldehyde
Ozonolysis of the alkene produces the ozonide, and its hydrolysis creates two carbon-oxygen double bonds and hydrogen peroxide. In the presence of some reducing agent as Zn, hydrolysis of the ozonide produces carbonyl compounds without any hydrogen peroxide.

Hydrolysis of ozonide of but-1-ene gives the formaldehyde and propionaldehyde.

The correct option is C.

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Similar questions

Q. The product of reductive hydrolysis of ozonide of 1-butene are:

Ozonolysis of alkenes gives ozonide which gives aldehydes and/or ketones. When a stream of $O_{3}$ is passed through a solution of alkene in an inert solvent at low temperature the molecule adds up to form ozonide. This ozonide is unstable and easily decompose either by reduction or hydrolysis and forms compound having. This $> C = O$ is known as ozonolysis.

Product P is

Q. A ketone A

(C_{4} H_{8} O)

, which undergoes haloform reaction gives compound B on reduction. B on heating with sulphuric acid gives a compound C which forms mono-ozonide D. D on hydrolysis in presence of zinc dust gives only acetaldehyde E. Identify A, B, C, D and E. Write the reactions involved.

Ozonolysis of alkenes gives ozonide which gives aldehydes and/or ketones. When a stream of $O_{3}$ is passed through a solution of alkene in an inert solvent at low temperature, the molecule adds up to form ozonide. This ozonide is unstable and easily decomposes either by reduction or hydrolysis and forms compound having the carbonyl group $> C = O$ . This is known as ozonolysis. 2-Methyl-but-2-ene on ozonolysis followed by reductive hydrolysis gives:

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H_{2} O_{2}

oxidizes ozonide to acid.

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