Hydrolysis of sucrose gives :
$S u c r o s e + H_{2} O ⇌ G l u c o s e + F r u c t o s e$
Equilibrium constant $K_{c}$ for the reaction is $2 \times 10^{13}$ at 300 K. Calculate $Δ G^{0}$ at 300 K.

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Solution

$Δ G^{o} = - R T l n K_{c}$
$= - 8.314 \times 300 \times l n (2 \times 10^{13})$
$= - 7.64 \times 10^{4} J / m o l$

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Similar questions

Q. Hydrolysis of sucrose gives glucose and fructose. The reaction takes place as: Sucrose

+ H_{2} O ⇌

Glucose

+

Fructose. The equilibrium constant

K_{c}

for this reaction is

2 \times 10^{13}

300 K

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Δ G^{\circ}

300 K

is:

Q. Hydrolysis of sucrose is given by the following reaction.

Sucrose + H_{2} O ⇌ Glucose+Fructose

If the equilibrium constant

(K_{c})

2 \times 10^{13}

300 K

, the value of

Δ_{r} G^{0}

at the same temperature will be :

Q. Hydrolysis of sucrose is given by the following reaction.

Sucrose + H_{2} O ⇌ Glucose + Fructose

If the equilibrium constant

(K_{C})

2 \times 10^{13} at 300 K

, The value of

Δ_{r} G^{\circ}

at the same temparature will be :

Sucrose (can Sugaro) is a disaccharide. One molecule of sucrose on hydrolysis gives............ .
(a) 2 molecules of glucose
(b) 2 molecules of glucose + 1 molecule of fructose
(c) 1 molecule of clucose + 1 molecule of fructose
(d) 2 molecules of fructose

Q. Acid or enzyme hydrolysis of sucrose to give an equimolar mixture of glucose and fructose is called:

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Hydrolysis of sucrose gives :Sucrose+H2O⇌Glucose+FructoseEquilibrium constant Kc for the reaction is 2×1013 at 300 K. Calculate ΔG0 at 300 K.

ΔGo=−RTlnKc=−8.314×300×ln(2×1013)=−7.64×104 J/mol

Hydrolysis of sucrose gives :
$S u c r o s e + H_{2} O ⇌ G l u c o s e + F r u c t o s e$
Equilibrium constant $K_{c}$ for the reaction is $2 \times 10^{13}$ at 300 K. Calculate $Δ G^{0}$ at 300 K.

$Δ G^{o} = - R T l n K_{c}$
$= - 8.314 \times 300 \times l n (2 \times 10^{13})$
$= - 7.64 \times 10^{4} J / m o l$