Hydrolysis of trichloro methane with aq. $K O H$ gives finally:

methanol

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chloral

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acetylene

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potassium formate

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Solution

The correct option is D potassium formate
$C H C l_{3} + 3 K O H_{(a q)} \to C H (O H)_{3} - H_{2} O - --- \to H C O O H K O H - -- \to H C O O K$

In this reaction first acid forms which converts further into formate.

Option D is correct.

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D_{2} O

a q . K O H

{F e C l}_{3}

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