Hyper conjugation is not possible in

H_{3} C - C H = C H_{2}

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H_{2} C = C H_{2}

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(C H_{3})_{2} C = C (C H_{3})_{2}

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Solution

The correct option is B $H_{2} C = C H_{2}$
Hyperconjuagtion of the delocalisation of sigma electrons of the C-H bond of the alpha carbon. B does not contain any alpha carbon and H and hence it does not exhibit hyperconjugation.

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