Question

$I.(17{)}^2+114-18=x$
$II.(26{)}^2-18\times 21=y$

• A. x > y
• B. x $\ge$ y
• C. x < y
• D. x $\le$ y
• E. x = y or the relationship cannot be established

Answer 1

The correct option is C x < y

Equation I
$(17{)}^2+114-18=x$
$\Rightarrow 289+8=x\Rightarrow x=297$
Equation II
$(26{)}^2-18\times 21=y$
$\Rightarrow 676-378=y\Rightarrow y=298$
Hence, y > x