Question

$I_2$ produced, when ozone reacts with moist $KI$, is used to convert $C_2{H}_{5}OH$ to $C{I}_{3}CHO$. The number of moles of ozone required to convert $1$ mol of $C_2{H}_{5}OH$ into $C{I}_{3}CHO$ is :

• A. $1$
• B. $2$
• C. $4$
• D. $3$

Answer 1

The correct option is C $4$

The reaction of ozone with $KI$ produces $I_2$ as shown below:
$O_3+2KI+H_{2}O\to 2KOH+I_2+O_2$

$I_2$ converts $C_2{H}_{5}OH$ to $C{H}_{3}CHO$ first and then, further to $C{l}_{3}CHO$.

The reactions are as follows:
$C_2{H}_{5}OH+I_2\to C{H}_{3}CHO+2HI$

$C{H}_{3}CHO+3I_2\to C{I}_{3}CHO+3HI$

Thus, a total of $4$ moles of iodine is required to convert $1$ mole of $C_2{H}_{5}OH$ to $C{I}_{3}CHO$.

$\therefore$ 4 moles of ozone required to produce 4 moles $I_2$

Option C is correct.