Question

I. 2$x^2$ - 7x + 6 = 0
II. 4$y^2$ = 9

• A. if x < y
• B. if x y
• C. if x = y
• D. if x y

Answer 1

The correct option is D

if x y

$\begin{array}{c}2x^2-7x+6=0\\ \Rightarrow 2x^2-4x-3x+6=0\\ \Rightarrow 2x\left(x-2\right)-3\left(x-2\right)=0\left(x-2\right)\left(2x-3\right)=0\\ \Rightarrow x=2,\frac{3}{2}\\ 4y^2=9\\ \Rightarrow y^2=\frac{9}{4}\\ \Rightarrow y=\pm \frac{3}{2}\\ \therefore x\ge y\end{array}$