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Question


I. 2Mn2+(aq)+4OH(aq)+O2(g)2MnO2(s)+2H2O(l)

II.MnO2(s)+2I(aq)+4H+(aq)Mn2+(aq)+I2(aq)+2H2O(l)

III. 2S2O23(aq)+I2(aq)S4O26(aq)+2I(aq)

Dissolved oxygen in water is determined by using the given redox reactions. When 3×103 moles O2 is dissolved per litre of water, then what will be the molarity of I produced in the given reaction?

A
3×103 M
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B
4×3×103 M
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C
2×3×103 M
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D
12×3×103 M
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Solution

The correct option is A 4×3×103 M
2Mn2+(aq)+4OH(aq)+O2(g)2MnO2(s)+2H2O(l)
MnO2(s)+2I(aq)+4H+(aq)Mn2+(aq)+I2(aq)+2H2O(l)
As per given redox reaction, 1 mole O2=2 moles MnO2=4 moles I

O2=3×103mol/L......... (given)

I=4×3×103mol/Li.e.4×3×103M

Hence, the correct option is (B)

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