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Molarity

I. 2Mn2+aq ...

Question

I. $2 M n^{2 +} (a q) + 4 O H^{-} (a q) + O_{2} (g) \to 2 M n O_{2} (s) + 2 H_{2} O (l)$

II. $M n O_{2} (s) + 2 I^{-} (a q) + 4 H^{+} (a q) \to M n^{2 +} (a q) + I_{2} (a q) + 2 H_{2} O (l)$

III. $2 S_{2} O_{3}^{2 -} (a q) + I_{2} (a q) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)$

Dissolved oxygen in water is determined by using the given redox reactions. When $3 \times 10^{3}$ moles $O_{2}$ is dissolved per litre of water, then what will be the molarity of $I^{-}$ produced in the given reaction?

3 \times 10^{- 3}

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4 \times 3 \times 10^{- 3}

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2 \times 3 \times 10^{- 3}

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\frac{1}{2} \times 3 \times 10^{- 3}

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Solution

The correct option is A $4 \times 3 \times 10^{- 3}$ M
$2 M n^{2 +} (a q) + 4 O H^{-} (a q) + O_{2} (g) \to 2 M n O_{2} (s) + 2 H_{2} O (l)$
$M n O_{2} (s) + 2 I^{-} (a q) + 4 H^{+} (a q) \to M n^{2 +} (a q) + I_{2} (a q) + 2 H_{2} O (l)$
As per given redox reaction, 1 mole $O_{2} = 2$ moles $M n O_{2} = 4$ moles $I^{-}$

$O_{2} = 3 \times 10^{3} m o l / L$ ......... (given)

$∴ I^{-} = 4 \times 3 \times 10^{3} m o l / L i . e . 4 \times 3 \times 10^{3} M$

Hence, the correct option is $(B)$

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Similar questions

2 M n^{2 +} (a q) + 4 O H^{-} (a q) + O_{2} (g) \to 2 M n O_{2} (s) + 2 H_{2} O (l)

M n O_{2} (s) + 2 I^{-} (a q) + 4 H^{+} (a q) \to M n^{2 +} (a q) + I_{2} (a q) + 2 H_{2} O (l)

2 S_{2} O_{3}^{2 -} (a q) + I_{2} (a q) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

2 M n^{2 +} (a q) + 4 O H^{-} (a q) + O_{2} (g) \to 2 M n O_{2} (s) + 2 H_{2} O (l)

M n O_{2} (s) + 2 I^{-} (a q) + 4 H^{+} (a q) \to M n^{2 +} (a q) + I_{2} (a q) + 2 H_{2} O (l)

2 S_{2} O_{3}^{2 -} (a q) + I_{2} (a q) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

S_{2} O_{3}^{2 -}

O_{2}

O_{2}

2 M n^{2 +} (a q) + 4 O ⊝ H (a q) + O_{2} (g) \to 2 M n O_{2} (s) + 2 H_{2} O (l)

O_{2}

1

M n^{2 +}

Z n (s) + 2 H^{+} (a q) ⟶ Z n^{2 +} (a q) + H_{2} (g)

2 [F e (C N)_{6}]^{3 -} (a q) + 2 O H^{-} (a q) + H_{2} O_{2} (a q) \to 2 [F e (C N)_{6}]^{4 -} (a q) + 2 H_{2} O (l)

2 [F e (C N)_{6}]^{3 -} (a q) + 2 O H^{-} (a q) + H_{2} O_{2} (a q) \to 2 [F e (C N)_{6}]^{4 -} (a q) + O_{2} (g) + 2 H_{2} O (l)

H_{2} C_{2} O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + H C_{2} O_{4} - (a q)

H C_{2} O_{5} - (a q) + H_{2} O (l) ⇌ H_{3} O + (a q) + C_{3} O_{4}^{2} - (a q)

K_{c l} = 5.9 \times 10^{- 2}

K_{c 2} = 6.4 \times 10^{- 5}

25^{\circ} C

K_{c}

(3)

H_{2} C_{2} O_{4} (a q) + 2 H_{2} O (l) ⇌ 2 H_{3} O + (a q) + C_{2} O_{4}^{2} - (a q)

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