Question

I. $2p^2+20p+50=0$
II. $q^2=25$

• A. If $p<q$
• B. If $p>q$
• C. If $p\le q$
• D. If $p\ge q$
• E. If $p=q$

Answer 1

Answer: (C)

If $p\le q$

Equation I
$2p^2+20p+50=0$
$\Rightarrow p^2+10p+25=0$
$\Rightarrow (p+5{)}^2=0$
$\Rightarrow p+5=0$
$\Rightarrow p=-5$

Equation II
$q^2=25$
$\Rightarrow q=\pm 5$
Hence, $p\le q$