Question

I. $2x^2+11x+12=0$
II. $2y^2+9y+45=0$

• A. $x>y$
• B. $x<y$
• C. $x\ge y$
• D. $x\le y$
• E. $x=y$ or relationship cannot be established

Answer 1

The correct option is A $x>y$

$(2x+8)(2x+3)=0$
$x=\frac{-8}{2},\frac{-3}{2}=-4,-1.5$
$(2y+10)(2y+9)=0$
$y=\frac{-10}{2},\frac{-9}{2}=-5,-4.5$
$-1.5,-4,-4.5,-5$
$x>y$