I. 2x + 3y = 14

II. 4x + 2y = 16

(a)

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(b)

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(d)

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(e)

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Solution

The correct option is B
(b)

2x + 3y = 14...........(i)

4x + 2y = 16..........(ii)

On solving, (i) x 2 -- (ii) we get,

4x + 6y - 4x - 2y = 28 - 16

4y = 12

y = 3

So, the value of x will be -

2x + 3 $\times$ 3 = 14

2x = 14 - 9 = 5

x = $\frac{5}{2}$

Suggest Corrections

Similar questions

$I . 2 x + 3 y = 14$

$I I . 4 x + 2 y = 16$

I . 2 x + 3 y = 14

I I . 4 x + 2 y = 16

x + y = 5, 2 x + 2 y = 10

x - y = 8, 3 x - 3 y = 16

2 x + y - 6 = 0, 4 x - 2 y - 4 = 0

2 x - 2 y - 2 = 0, 4 x - 4 y - 5 = 0

4 x + 3 y = 16

2 x + 2 y = 9

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