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Question

I. 3p2+17p+10=0
II. 10q2+9q+2=0

A
If p is greater than q
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B
If p is smaller than q
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C
If p is equal to q
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D
If p is either equal to or greater than q
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E
If p is either equal to or smaller than q
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Solution

The correct option is B If p is smaller than q
Equation I
3p2+17p+10=0
3p2+15p+2p+10=0
3p(p+5)+2(p+5)=0
(p+5)(3p+2)=0
p=2 or 23

Equation II
10q2+5q+4q+2=0
5q(2q+1)+2(2q+1)=0
(2q+1)(5q+2)=0
q=12 or 25
Hence, p<q

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