I -3 p - 2-17 p -10-0 1-II- 10 q - 2-9 q -2-0 A- p is greater than qB- p is equal to qC- p is smaller than qD- p is either equal to or greater than qE- p is either equal or smaller than q

The correct option is C p is smaller than q I. ⇒ 3p^2+15p +2p+10 =0 ⇒ 3p(p+5)+2(p+5)=0 ⇒ (p+5)(3p+2)=0 p = 5 or 2/3 II. ⇒ 10q^2+5q+4q+2 =0 ⇒ 5q(2q+1)+2(2q+ ...

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Quantitative Aptitude

Functions

I .3 p ∧ 2+17...

Question

$I .3 p^{2} + 17 p + 10 = 0 I I . 10 q^{2} + 9 q + 2 = 0$

p is greater than q

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p is smaller than q

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p is equal to q

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p is either equal to or greater than q

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p is either equal or smaller than q

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Solution

The correct option is B p is smaller than q

$I . \Rightarrow 3 p^{2} + 15 p + 2 p + 10 = 0 \Rightarrow 3 p (p + 5) + 2 (p + 5) = 0 \Rightarrow (p + 5) (3 p + 2) = 0 p = - 5 o r - \frac{2}{3} I I . \Rightarrow 10 q^{2} + 5 q + 4 q + 2 = 0 \Rightarrow 5 q (2 q + 1) + 2 (2 q + 1) = 0 \Rightarrow (2 q + 1) (5 q + 2) = 0 \Rightarrow q = - \frac{1}{2} o r - \frac{2}{5}$
Hence, p < q

Suggest Corrections

I.3p2+17p+10=0II.10q2+9q+2=0

The correct option is B p is smaller than q I.⇒3p2+15p+2p+10=0⇒3p(p+5)+2(p+5)=0⇒(p+5)(3p+2)=0p=−5or−23II.⇒10q2+5q+4q+2=0⇒5q(2q+1)+2(2q+1)=0⇒(2q+1)(5q+2)=0⇒q=−12or−25 Hence, p < q

$I .3 p^{2} + 17 p + 10 = 0 I I . 10 q^{2} + 9 q + 2 = 0$