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Question

I. 3p+2q58=0
II. 4q+4p=92

A
p is greater than q
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B
p is less than q
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C
p is equal to q
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D
p is either equal to or greater than q
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E
p is either equal to or smaller than q
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Solution

The correct option is A p is greater than q
We have,
I. 3p + 2q = 58 ...(i)
II. 4p + 4q = 92
2p + 2q = 46 ...(ii)
On substracting Eq. (ii) from Eq. (i), we get
p = 12
From Eq. (i), 3×12+2q=58
2q=5836=22
q=11
p>q

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