I- 3 p-2 q-58-0II- 4 q -4 p -92A- p is greater than qB- p is smaller than qC- p is equal is equal to or greater than qD- p is equal to qE- p is either equal to or smaller than q

The correct option is A p is greater than qWe have, I. 3p + 2q = 58 ...(i) II. 4p + 4q = 92 ⇒ 2p + 2q = 46 ...(ii) On subtracting Eq. (ii) from Eq.(i), we ge ...

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Standard VI

Mathematics

Word Problems

I. 3 p+2 q-58...

Question

I. 3p + 2q - 58 = 0
II. 4q + 4p = 92

p is greater than q

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p is smaller than q

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p is equal to q

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p is equal is equal to or greater than q

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p is either equal to or smaller than q

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Solution

The correct option is A p is greater than q
We have,
I. 3p + 2q = 58 ...(i)
II. 4p + 4q = 92
$\Rightarrow 2 p + 2 q = 46$ ...(ii)
On subtracting Eq. (ii) from Eq.(i), we get
p = 12
From Eq. (i)
$3 \times 12 + 2 q = 58$
$\Rightarrow 2 q = 58 - 36 = 22$
$\Rightarrow q = 11$
Hence, p > q

Suggest Corrections

I. 3p + 2q - 58 = 0 II. 4q + 4p = 92

The correct option is A p is greater than qWe have, I. 3p + 2q = 58 ...(i) II. 4p + 4q = 92 ⇒2p+2q=46 ...(ii) On subtracting Eq. (ii) from Eq.(i), we get p = 12 From Eq. (i) 3×12+2q=58 ⇒2q=58−36=22 ⇒q=11 Hence, p > q

I. 3p + 2q - 58 = 0
II. 4q + 4p = 92

The correct option is A p is greater than q
We have,
I. 3p + 2q = 58 ...(i)
II. 4p + 4q = 92
$\Rightarrow 2 p + 2 q = 46$ ...(ii)
On subtracting Eq. (ii) from Eq.(i), we get
p = 12
From Eq. (i)
$3 \times 12 + 2 q = 58$
$\Rightarrow 2 q = 58 - 36 = 22$
$\Rightarrow q = 11$
Hence, p > q