(i).3u+4v=5

5u+6v=1

Solve this equation by elimination, cross multiplication, and substitution .

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Solution

3u+4v=5-------(1)
5u+6v=1-------(2)
(1)5=15u+20v=25----(3)
(2)3=15u+18v=3-----(4)
(3)-(4)=2v=22
v=22/2=11
put v=11 in equation 1
3u+44=5
3u=5-44=-39
u=-39/3=-13
u=-13
Hope you understand this
please lime if you are satisfied

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