I. $3 x^{2} - 15 x + 18 = 0$

II. $y^{2} - 3 y - 4 = 0$

Relationship between x and y cannot be established

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x > y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
Relationship between x and y cannot be established

$3 x^{2} - 15 x + 18 = 0$

$\Rightarrow x^{2} - 5 x + 6 = 0$

$\Rightarrow x = 2, 3$

$y^{2} - 3 y - 4 = 0$

$\Rightarrow y = 4, - 1$

$\Rightarrow$ No relationship can be established between x and y.

Suggest Corrections

Similar questions

$I. 3x^2 - 15x + 18 = 0$

$II. y^2 - 3y - 4 = 0$

I . x^{2} - 8 x + 15 = 0

I I . y^{2} - 3 y + 2 = 0

I . x^{2} + 5 x + 6 = 0

I I . y^{2} + 3 y + 2 = 0

I. 3 $x^{2}$ + 8x + 4 = 0

II. 4 $y^{2}$ - 19y + 12 = 0

I . (6 x^{2} + 17) - (3 x^{2} + 20) = 0

I I . (5 y^{2} - 12) - (9 y^{2} - 16) = 0

Join BYJU'S Learning Program