I- 3 x- 2-23 x-44-0 1II- - y- 2-20 y-33-0 A- x y C- x - yD- x - yE- Relationship between x and y cannot be established

The correct option is C x≤ yEquation I 3x^2+23x+44=0 3x^2+12x+11x+44=0 3x(x+4)+11(x+4)=0 (3x+11)(x+4)=0 x= 4, x= 11/3 Equation II 3y^2+20y+33=0 3y^2+11y+9y+33= ...

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Byju's Answer

Standard XII

Mathematics

Derivative of Standard Functions

I. 3 x∧ 2+23 ...

Question

$I . 3 x^{2} + 23 x + 44 = 0 I I . 3 y^{2} + 20 y + 33 = 0$

x < y

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x > y

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x \geq y

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x \leq y

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Relationship between x and y cannot be established

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Solution

The correct option is D $x \leq y$
Equation I
$3 x^{2} + 23 x + 44 = 0$
$3 x^{2} + 12 x + 11 x + 44 = 0$
$3 x (x + 4) + 11 (x + 4) = 0$
$(3 x + 11) (x + 4) = 0$
$x = - 4, x = - \frac{11}{3}$
Equation II
$3 y^{2} + 20 y + 33 = 0$
$3 y^{2} + 11 y + 9 y + 33 = 0$
$y (3 y + 11) + 3 (3 y + 11) = 0$
$(3 y + 11) (y + 3) = 0$
$∴ y = - 3, y = - \frac{11}{3}$
Hence $x \leq y$

Suggest Corrections

I. 3x2+23x+44=0II. 3y2+20y+33=0

The correct option is D x≤yEquation I 3x2+23x+44=0 3x2+12x+11x+44=0 3x(x+4)+11(x+4)=0 (3x+11)(x+4)=0 x=−4,x=−113 Equation II 3y2+20y+33=0 3y2+11y+9y+33=0 y(3y+11)+3(3y+11)=0 (3y+11)(y+3)=0 ∴y=−3,y=−113 Hence x≤y

$I . 3 x^{2} + 23 x + 44 = 0 I I . 3 y^{2} + 20 y + 33 = 0$