I- 3 x 2-7 x -2-0II 2 y 2-11 y -15-0A- If x - yB- If x yD- If x - yE- If x - y

The correct option is B If x lt;yI. 3x^2 7x+2=0 or, 3x^2 6x x+2=0 or, (x 2)(3x 1)=0 or, x= 2,1/3 II. 2y^2 11y+15=0 or, 2y^2 6y 5y+15=0 or, (2y 5)(y 3)=0 or ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Addition and Subtraction of Terms

I. 3 x 2-7 x ...

Question

I. $3 x^{2} - 7 x + 2 = 0$
II $2 y^{2} - 11 y + 15 = 0$

x < y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x > y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x \geq y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x \leq y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A If $x < y$
I.
$3 x^{2} - 7 x + 2 = 0$
or, $3 x^{2} - 6 x - x + 2 = 0$
or, $(x - 2) (3 x - 1) = 0$
or, $x = 2, \frac{1}{3}$

II.
$2 y^{2} - 11 y + 15 = 0$
or, $2 y^{2} - 6 y - 5 y + 15 = 0$
or, $(2 y - 5) (y - 3) = 0$
or, $y = \frac{5}{2}, 3$
Hence, $y > x$

Suggest Corrections

I. 3x2−7x+2=0 II 2y2−11y+15=0

The correct option is A If x<yI. 3x2−7x+2=0 or, 3x2−6x−x+2=0 or, (x−2)(3x−1)=0 or, x=2,13 II. 2y2−11y+15=0 or, 2y2−6y−5y+15=0 or, (2y−5)(y−3)=0 or, y=52,3 Hence, y>x

I. $3 x^{2} - 7 x + 2 = 0$
II $2 y^{2} - 11 y + 15 = 0$

The correct option is A If $x < y$
I.
$3 x^{2} - 7 x + 2 = 0$
or, $3 x^{2} - 6 x - x + 2 = 0$
or, $(x - 2) (3 x - 1) = 0$
or, $x = 2, \frac{1}{3}$

II.
$2 y^{2} - 11 y + 15 = 0$
or, $2 y^{2} - 6 y - 5 y + 15 = 0$
or, $(2 y - 5) (y - 3) = 0$
or, $y = \frac{5}{2}, 3$
Hence, $y > x$