I. (3x-2)/y=(3x+6)/(y+16)
II. (x+2)/(y+4)=(x+5)/(y+10)

if x > y

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if x < y

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if x $\geq$ y

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if x $\leq$ y

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if x = y or relation cannot be established between 'x' and 'y'.

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Solution

The correct option is B
if x < y

(3x-2)/y=(3x+6)/(y+16)
48x-8y=32 ...(i)
(x+2)/(y+4)=(x+5)/(y+10)
y=2x ....(ii)
From equation (i) and (ii)
x=1, y=2
y>x

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