I- 4 x2-19 x-12-0II- 3 y 2-8 y -4-0A- x - yB- x-y C- x - yD- x - yE- x - y or relationship cannot be established

The correct option is B x gt; y(x 4)(4x 3) = 0 x = 4, 3/4 (y + 2)(3y + 2) = 0 y = 2, 2/3 4, 3/4, 2/3, 2 x gt; y ...

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Algebraic Identities

I. 4 x2-19 x+...

Question

I. $4 x^{2} - 19 x + 12 = 0$
II. $3 y^{2} + 8 y + 4 = 0$

x > y

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x < y

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x \geq y

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x \leq y

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x = y

or relationship cannot be established

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