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Question

I. 4x28x+3=0
II. 2y27y+6=0

A
If x<y
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B
If xy
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C
If x=y
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D
If xy
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E
If x>y
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Solution

The correct option is B If xy
Equation I
4x28x+3=0
4x26x2x+3=0
2x(2x3)1(2x3)=0
(2x1)(2x3)=0
x=12 or 32

Equation II
2y27y+6=0
2y24y3y+6=0
2y(y2)3(y2)=0
(2y3)(y2)=0
y=32 or 2
Hence, xy

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