Question

I. $9x^2-9x+2=0$
II. $9y^2-3y-2=0$

• A. if x > y
• B. if x < y
• C. if x <= y
• D. if x >= y
• E. if x = y or relationship between x and y cannot be determined

Answer 1

The correct option is E if x = y or relationship between x and y cannot be determined

$9x^2-9x+2=09x^2-6x-3x+2=03x(3x-2)-1(3x-2)=0(3x-2)(3x-1)=0x=\frac{2}{3},\frac{1}{3}$
$Also,9y^2-3y-2=09y^2-6y+3y-2=03y(3y-2)+1(3y-2)=0(3y-2)(3y+1)=0y=-\frac{1}{3},\frac{2}{3}$
$\therefore$ Relationship between x and y cannot be determined.