Question

$I$. A $0.5M$ solution of calcium sulfate can be prepared by dissolving $18.04g$ of calcium sulfate into a total solution volume of $500mL$
$II$. The molar mass of calcium sulfate is $72.14g/mol$.

• A. Statement $I$ is true, Statement $II$ is true
• B. Statement $I$ is true, Statement $II$ is false
• C. Statement $I$ is false, Statement $II$ is true
• D. Statement $I$ is false, Statement $II$ is false

Answer 1

The correct option is D Statement $I$ is false, Statement $II$ is false

Molar mass of $CaS{O}_4=40+32+64=136g/mol$

Molarity $=\frac{\text{Mass of}CaS{O}_4}{\text{Molar mass of}CaS{O}_4}\times \frac{1000}{\text{V (in mL)}}=\frac{18}{136}\times 2=\frac{36}{136}=0.264M$

So, both statements are false.