Question

$\left(I\right)$. A $1M$ solution of sucrose $(C_{12}{H}_{22}{O}_{11}$) can be prepared by dissolving $342.20g$ of sucrose to make $1000mL$ of sugar water solution.
$\left(II\right)$. The molar mass of sucrose is $342.20g$ and $1L$ of water is the same as $100g$.

• A. Statement $I$ is true, Statement $II$ is true
• B. Statement $I$ is true, Statement $II$ is false
• C. Statement $I$ is false, Statement $II$ is true
• D. Statement $I$ is false, Statement $II$ is false

Answer 1

Answer: (B)

Statement $I$ is true, Statement $II$ is false

Sucrose $\left(C_{12}{H}_{22}{O}_{11}\right)$ has molar mass of $342.20g$

Molarity of Sucrose $=\frac{\text{Mass of Sucrose}}{\text{Molar mass}}\times \frac{1000}{\text{V (in mL)}}=\frac{342.2}{342.2}\times \frac{1000}{1000}=1M$

Density of water $=1g/mL=1kg/L$

So, $1Litre$ of water weighs $1kg=1000g$