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Isomerism in Coordination Compounds

i A black min...

Question

(i) A black mineral (A) on heating in presence of air gives a gas (B).
(ii) The mineral (A) on reaction with dilute $H_{2} S O_{4}$ gives a gas (C) and solution of a compound (D).
(iii) On passing gas (C) into an aqueous solution (B), a white turbidity is obtained.
(iv) The aqueous solution of compound (D) on reaction with potassium ferricyanide gives a blue compound (E).
Compounds (A) to (E) are identified as:
(A) : $F e S$ , (B) : $S O_{2}$ , (C) : $H_{2} S$ , (D) : $F e S O_{4}$ and (E) : $K F e^{I} I [F e^{I} I I (C N)_{6}]$
If true enter 1, else enter 0.

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Solution

The black mineral (A) is ferrous sulphide, $F e S$ .
The gas obtained on heating FeS in presence of air is sulphur dioxide, $S O_{2}$ .
(i) $2 F e S + 3.5 O_{2} ⟶ F e_{2} O_{3} + 2 S O_{2}$
FeS reacts with dil sulphuric acid to form hydrogen sulphide gas and the compound (D) which is ferrous sulphate, $F e S O_{4}$ .
(ii) $F e S + H_{2} S O_{4} ⟶ F e S O_{4} + H_{2} S$
FeS reacts with gas (C) which is $H_{2} S$ and gives white turbidity of S.
(iii) $S O_{2} + 2 H_{2} S ⟶ 2 H_{2} O + 3 S$
Ferrous sulphate reacts with potassium ferricyanide to form a blue compound (E), which is $K F e^{I} I [F e^{I} I I (C N)_{6}]$ .
(iv) $F e S O_{4} + K_{3} [F e (C N)_{6}] ⟶ K I I F e [I I I [F e (C N)_{6}] + K_{2} S O_{4}$

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Q. An aqueous solution of salt (A) gives a white crystalline precipitate (B) with NaCl solution. The filtrate gives a black precipitate (C) when

H_{2} S

is passed through it. Compound (B) dissolves in hot water and the solution gives yellow precipitate (D) on treatment with potassium iodine and on cooling. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Compounds (A) to (D) are identified as:

P b (N O_{3})_{3}

P b C l_{2}

P b S

P b I_{2}

If true enter 1, else enter 0.

Q. Read the following statements:
(i) A white amorphous powder (A) on strongly heating gives a colourless non-combustile gas (B) and solid (C).
(ii) The gas (B) turns lime water milky and turbidity disappear with the passage of excess of gas.
(iii) The solution (C) in dilute HCl gives a white precipitate with an aqueous solution of

K_{4} [F e (C N)_{6}]

.
(iv) The solution of (A) gives a white precipitate (D) on pasiing

H_{2} S

in presence of excess of

N H_{4} O H

.
Compound (A) to (D) are identified as:
(A) :

Z n C O_{3}

C O_{2}

Z n O

Z n S

If true enter 1, else enter 0.

A black colored compound (A) on reaction with

d i l . H_{2} S O_{4}

gives a gas (B) which on passing in a solution of acid (C) gives white turbidity (D). Gas (B) when passed in an acidified solution of a compound (E) gives a black precipitate (F) which is soluble in hot concentrated (C). After boiling this solution when an excess of ammonia solution is added, a blue-colored compound (G) is formed. To the solution of (E), on the addition of acetic acid and aqueous potassium ferrocyanide, a chocolate brown precipitate (H) is formed. On the addition of an aqueous solution of

B a C l_{2}

to an aqueous solution of (E), white precipitate insoluble in

H N O_{3}

The gas (B) on passing through an acid (C) gives white turbidity (D) because :

A black colored compound (A) on reaction with dilute

H_{2} S O_{4}

gives a gas (B) which on passing in a solution of acid (C) gives white turbidity (D). Gas (B) when placed in an acidified solution of a compound (E) gives a precipitate (F) soluble in dilute

H N O_{3} .

After boiling this solution, when an excess of

N H_{4} O H

is added, blue colored compound (G) is formed. To this solution on addition of

C H_{3} C O O H

K_{4} [F e (C N)_{6}]

, a chocolate precipitate (H) is obtained. On the addition of an aqueous solution of

B a C l_{2}

to an aqueous solution of E, a white ppt insoluble in

H N O_{3}

An aqueous solution of a salt (A) gives white precipitate (B) with sodium chloride solution. The filtrate gives a black precipitate. (C) When $H_{2} S$ is passed into it. Compound (B) dissolves in hot water and the solution gives a yellow precipitate (D) on treatment with sodium iodide. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Identify the compound (A) to (D).

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