ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively. Show that ΔABE≅ΔACF
In the given figure, BE and CF are two equal altitudes of ΔABC.Show that (i) ΔABE≅ ΔACF, (ii) AB=AC.
ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that
(i) △ABE≅△ACF
(ii) AB=AC, i.e., ABC is an isosceles triangle.