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Question

I am a number between 20 and 30. If you divide 47 and 92 by me, the remainders are 3 and 4,respectively. Which number am I?


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Solution

Step 1;Here reminder are 3 and 4

47-3=44 and 92-4=88

So ,if we divide 44 and 88 by required number it will be completely divisible by that number.

Step 2; Prime factorization of 44 and 88 are given below,

44=2×2×1188=2×2×2×11

Common factors are 2and 11
Therefore HCF =2×11=22
Hence, answer is 22


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