The correct option is C 336
There are nine numbers ( 331, 332 .... 339) between 330 and 340.
Out of the numbers, only 336 is divisible by both 2 and 3 because its last digit "6" is an even number and its sum of digits (3+3+6=12) is a multiple of 3.
As 336 divisible by both 2 and 3, it is divisible by 6 also.
∴ 336 is the required number.