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Question

I am the smallest number which is 3 more than a number which is completely divisible by 15 and 20. Identify me.


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Solution

The smallest number, which is completely divisible by 15 and 20 is the LCM of both the numbers.

So, by prime factorisation we get,
15=3×5
20=2×2×5

LCM of 15 and 20 is 2×2×3×5=60

The required number is 3 more than 60 i.e 63.

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