I: An element that has the electron configuration ${1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{3} {4 s}^{2}$ is a transition element.
II: In atoms of transition elements, the 1s, 2s, 2p, 3s and 3p orbitals are completely filled in the ground state.

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Solution

General configuration of transition element is $(n - 1) d^{1 - 10} {n s}^{0, 1, 2}$
Therefore the given element is transition element. Also, $1 s, 2 s, 2 p, 3 s$ and $3 p$ orbitals are fully filled in the ground state, but second statement is not the correct explanation of first statement.

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The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{2}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

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