I apply an electric field of 105N/C on a conductor of cross section 4mm2 and I get a current of 1A. If I want to change the current to 0.3A, what is the electric field I need to apply?
A
3×104N/C
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B
5×104N/C
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C
4×104N/C
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D
2×104N/C
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Solution
The correct option is A3×104N/C Given E1=105N/C I1=1A
A = 4mm2 J1 = I1/A=0.25×106A/m2