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Question

I apply an electric field of 105N/C on a conductor of cross section 4mm2 and I get a current of 1A. If I want to change the current to 0.3A, what is the electric field I need to apply?

A
3×104N/C
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B
5×104N/C
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C
4×104N/C
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D
2×104N/C
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Solution

The correct option is A 3×104N/C
Given E1 = 105N/C
I1 = 1A
A = 4mm2
J1 = I1/A = 0.25×106A/m2

We need I = 0.3 A
So J2 = 0.75×106A/m2

We know that
E α J
So, E1J1 = E2J2

E2 = 3×104N/C

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