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Question

(i)C6H5CH2 (ii)C6H5CH2CH2 (iii)C6H5CHCH3 (iv)C6H5C(CH3)2
Stability order of the following carbocations is

A
II<I<III<IV
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B
II<III<I<IV
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C
III<I<II<IV
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D
IV<III<I<II
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Solution

The correct option is A II<I<III<IV
The order of stability of carbocations are
Primary<secondary<tertiary
Compounds III and IV are secondary carbocations. Between these two IV is more stable when compared to III because IV is stabilized by two methyl groups and one benzene ring whereas in the III compound carbocation is stabilized by only one methyl and one benzene ring.
In I and II,I is more stable than II because it is stabilized by benzene rind which is adjacent to carbocation whereas in the compound II the carbocation is stabilized by the methyl group and benzene ring is a bit far from the carbocation. so, it contributes to the stabilization of carbocation is less when compared to the compound I
So the correct order is
II<I<III<IV

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