Question

(i) Calculate the number of electrons which will together weighs one gram.
(ii) Calculate the mass and charge of one mole of electrons.

Answer 1

The number of electrons which will weigh 1 g is $\frac{{10}^{-3}}{9.11\times {10}^{-31}}=1.098\times {10}^{27}$ .

Mass of one mole of electrons is $9.11\times {10}^{-31}\times 6.023\times {10}^{23}=5.486\times {10}^{-7}$kg.

Charge of 1 mole of electrons is $1.602\times {10}^{-19}\times 6.023\times {10}^{23}=9.647\times {10}^{4}C$.