Given that,
Force →F=5^i+3^j+2^k
Displacement →s=3^i−^j+2^k
We know that,
The work done is
W=→F⋅→s
W=(5^i+3^j+2^k)⋅(3^i−^j+2^k)
W=15−3+4
W=16J
Hence, this is the required solution
(b). we know that,
Work done = force ∙ displacement
W=→F⋅→d
W=Fdcosθ
Where, θ is the angle between →F and →d
This is a scalar product and work is a scalar