Question

(i) $CH\equiv CH\stackrel{\left(A\right)}{\to }\left(B\right)\stackrel{\left(O\right)}{\to }C{H}_{3}COOH\stackrel{\left(C\right)}{\to }C{H}_{2}ClCOOH$

Complete the given reactions:

Answer 1

(i) $HC\equiv CH+H_{2}O\stackrel{\underset{\text{(A)}}{40\%H_{2}S{O}_4/1\%HgS{O}_4}}{\to }\underset{\text{(B)}}{C{H}_3-CHO}\stackrel{\left(O\right)}{\to }C{H}_{3}COOH\stackrel{\underset{\text{(C), Hell Vohlard Zelinsky reaction}}{redP/C{l}_2}}{\to }C{H}_{2}ClCOOH$

Hydration of acetylene followed by keto enol tautomerism gives acetaldehdye. Oxidation of acetaldehyde gives acetic acid. Alpha H atom of acetic acid is then replaced with Cl atom.